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File Upload #33

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@vladinator1000

I'm working on an example repo and was wondering, what would be the simplest way to implement that? This is what I tried without GraphQL:

@app.route('/upload', methods=['POST'])
def uploadFile():
	for key in request.files:
		file = request.files[key]
		file.save(os.path.join(UPLOAD_FOLDER, file.filename))
	
	return 'uploaded'

This is what I used in Node.js, would love to do something like that for Flask in Python.

If it's not supported by flask-graphql I'd be happy to work on a pull request. Also, how would you test this without a browser, using Graphiql, Postman or something like that?

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